Question

The mean pulse rate in beats per minute of adult males is 69 bpm. For a random sample of 161 males, the mean pulse rate is 70.1 bpm and the standard deviation is 11.2 bpm. find the value of the test statistic. Round to two decimal places.

Answer 1

solution:

this is the two tailed test .  

The null and alternative hypothesis is ,

H0 :   = 69

Ha :     69

Test statistic = z

= ( - ) / / n

= (70.1-69) / 11.2 / 161

= 1.25