What sample size is needed if a ±1.5 lbs. margin of error is needed for computing the 95% confidence interval of the mean weight of U.S. adult males? Assume a population standard deviation of 12 lbs.
Margin of Error (MOE) = 1.5
= 12 (population standard deviation)
Let n be the required sample size
For 95% confidence interval the level of significance () = 0.05
Critical value = = = = 1.960 (we get this value from z table and here we ignore the sign we only need the value)
sample size can not be in fraction so round off n
so, n = 246
Answer : The required sample size is 246
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