In a recent poll, 250 people were asked if they liked dogs, and 17% said they did. Find the margin of error of this poll, at the 99% confidence level. Give your answer to three decimals
Solution :
Given that,
n = 250
Point estimate = sample proportion =
= 0.17
1 -
= 1-0.17 =0.83
At 99% confidence level the z is ,
= 1 - 99% = 1 - 0.99 =
0.01
/ 2 = 0.01 / 2 = 0.005
Z/2
= Z0.005 = 2.576 ( Using z table )
Margin of error = E = Z
/ 2 * (
(((
* (1 -
)) / n)
= 2.576* (((0.17*0.83)
/250 )
E = 0.061
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