With a mean of 92.12
and a standard deviation of 2.43
Finding Values: A baseball fan wishes to identify the
fastballs among the fastest 20% of all such pitches. Above what
speed must a fastball be in order to be included in the fastest
20%? Round your answer to the nearest 0.1 mph.
Solution:-
Given that,
mean = = 92.12
standard deviation = = 2.43
Using standard normal table,
P(Z > z) = 20%
= 1 - P(Z < z) = 0.20
= P(Z < z) = 1 - 0.20
= P(Z < z ) = 0.80
= P(Z < 0.84 ) = 0.80
z = 0.84 ( using z table )
Using z-score formula,
x = z * +
x = 0.84 * 2.43+92.12
x =94.16
x=94.2
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