Question

I am being asked to complete a chi square analysis given a set of data and a null and alternative hypothesis. We were asked to buy a bag of m&ms and separate them by their color and count how many of each color was in the bag.

Data:

Color	Score
Red	21
Blue	34
Orange	30
Brown	33
Yellow	14

Hypotheses:

Null: An equal number of M&M's of each color are distributed into the bags.

Alternative: An unequal number of M&M's of each color are distributed into the bags.

What is the Chi square value and the degrees of freedom.

-I am confused because I am unsure as to how to find the expected values in order to complete the chi square analysis and have been unable to find anything on the internet on one-way tables.

Answer 1

Sol:

Total n=132

Expected frequencies=n*1/k=132*1/5=26.4

k=5 (red,blue,orange,brown,yellow)

chi sq test statistic,chi sq=11.257

k=5

degrees of freedom=k-1=5-1=4

=CHISQ.DIST.RT(11.25758,4)

0.023816756

p<0.05

Reject Ho

Accept Ha

An unequal number of M&M's of each color are distributed into the bag