Surgical complications: A medical researcher wants to construct a 98% confidence interval for the proportion of knee replacement surgeries that result in complications.
) Estimate the sample size needed if no estimate of
p
is available.
A sample of __operations is needed to obtain a 98%confidence interval with a margin of error of 0.08 when no estimate of p is available. |
Solution :
Given that,
= 0.5
1 - = 0.5
margin of error = E = 0.08
At 98% confidence level the z is,
= 1 - 98%
= 1 - 0.98 = 0.02
/2 = 0.01
Z/2 = 2.326 ( Using z table )
Sample size = n = (Z/2 / E)2 * * (1 - )
= (2.326 / 0.08)2 * 0.5 * 0.5
=195
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