Question

Claim: The mean pulse rate (beats per minute) of adult males is equal to 69 bpm. For a sample of 128 adult males, the mean pulse rate is 68.4 bpm and the standard deviation is 11.5 bpm. Find the value of the test statistic. The value of the test statistic is __ (round to two decimal places).

Answer 1

this is the two tailed test .  

The null and alternative hypothesis is ,

H0 :   = 69

Ha :     69

Test statistic = z

= ( - ) / / n

= (68.4-69) / 11.5 / 128

= -0.59