Question

The director of research and development is testing a new drug. She wants to know if there is evidence at the 0.01 level that the drug stays in the system for more than 395 minutes. For a sample of 74 patients, the mean time the drug stayed in the system was 399 minutes. Assume the population standard deviation is 23. Find the P-value of the test statistic. Round your answer to four decimal places.

Answer 1

Solution :

This is the right tailed test .

The null and alternative hypothesis is ,

H0 :   = 395

Ha : > 395

Test statistic = z

= ( - ) / / n

= (399 - 395) / 23 / 74 =  1.496

Test statistic = 1.496

P(z > 1.496) = 1 - P(z < 1.496) = 1 - 0.9327 = 0.0673

P-value = 0.0673