Company A is developing a new pregnancy test. Based on their experiments, the test gives the correct result about 73% of the time, meaning the test result is positive when the person is pregnant, it is negative when the person is not pregnant.
Suppose that 45% of women who take the test are pregnant.
If the test result is positive, what is the probability that the person is truly pregnant?
You can express your answer as a fraction, decimal, or a percentage. If you answer in decimal, include at least 3 digits after the decimal point. If you answer is a percentage, make sure to include a % sign in your answer.
From the given data, the following Table is calculated:
Pregnant | Not pregnant | Total | |
Test is positive | 0.45 X 0.73 = 0.3285 | 0.1485 | 0.477 |
Test is negative | 0.1215 | 0.55 X 0.73 = 0.4015 | 0.523 |
Total | 0.45 | 0.55 | 1.00 |
P(Pregnant/ Test is positive) = P(Pregnant AND Test is positive) P(Test is positive)
=0.3285/0.477
= 0.689
So,
Answer is:
0.689
Get Answers For Free
Most questions answered within 1 hours.