The table below shows the number of survey subjects who have received and not received a speeding ticket in the last year, and the color of their cars.
Speeding Ticket | No Speeding Ticket | Total | |
Red Car | 156 | 113 | 269 |
Not Red Car | 172 | 82 | 254 |
Total | 328 | 195 | 523 |
Find the probability that a randomly chosen person:
a) Has a red car.
b) Has a speeding ticket.
c) Has a speeding ticket given they have a red
car.
d) Has a red car given they have a speeding
ticket.
e) Has a red car and got a speeding ticket.
f) Has a red car or got a speeding ticket.
Write your answers in decimal form, rounded to the nearest
thousandth.
Add Work
a) P(Red Car) = 269/523 = 0.514
b) P(Speeding Ticket) = 328/523 = 0.627
c)P(Speeding Ticket | Red Car) = P(Speeding Ticket and Red Car)/P(Red Car) = 156/269 =0.579
d)P(Red Car | Speeding Ticket) = P(Speeding Ticket and Red Car)/P(Speeding Ticket) = 156/328 =0.475
e)P(Red Car and Speeding Ticket) = 156/523 = 0.298
f)P(Red Car or Speeding Ticket) = P(Red Car) + P(Speeding Ticket) - P(Red Car and Speeding Ticket)
=(269+328-156)/523 =441/523 = 0.843
Please ike the answer.
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