Question

Suppose that diastolic blood pressures of adult women in the United States are approximately normally distributed with mean 80.5 and standard deviation 9.9. What proportion of women have blood pressure greater than 72.9 ?

Write only a number as your answer. Round to 4 decimal places (for example 0.0048). Do not write as a percentage.

Answer 1

We are given the distribution here as:

The proportion of women that have blood pressure greater than 72.9 is computed here as:

P(X > 72.9)

Converting it to a standard normal variable, we have here:

Getting it from the standard normal tables, we have here:

Therefore 0.7787 is the required proportion here.