Question

According to a Pew Research Center study, in May 2011, 32% of all American adults had a smart phone (one which the user can use to read email and surf the Internet). A communications professor at a university believes this percentage is higher among community college students.

Part A She selects 304 community college students at random and finds that 105 of them have a smart phone. Then in testing the hypotheses: H0: p = 0.32 versus Ha: p > 0.32, what is the test statistic? z = . (Please round your answer to two decimal places.)

Part B She selects 351 community college students at random and finds that 130 of them have a smart phone. In testing the hypotheses: H0: p = 0.32 versus Ha: p > 0.32, she calculates the test statistic as z = 2.0230. Then the p‑value = . (Please round your answer to four decimal places.)

Answer #1

Solution :

Given that,

P_{0} = 0.32

1 - P_{0} = 1 - 0.32 = 0.68

Part A)

n = 3014

x = 105

= x / n = 105 / 304 = 0.3454

z = - P_{0} / [P_{0 *} (1 -
P_{0} ) / n]

= 0.3454 - 0.32 / [(0.32 * 0.68) / 304]

= 0.949

Test statistic = 0.95

Part B)

Given that,

This is the right tailed test ,

z = 2.0230

Using standard normal table,

P(z > 2.0230) = 1 - P(z < 2.0230) = 1 - 0.9785 = 0.0215

P-value = 0.0215

According to a Pew Research Center study, in May 2011, 32% of
all American adults had a smart phone (one which the user can use
to read email and surf the Internet). A communications professor at
a university believes this percentage is higher among community
college students. She selects 351 community college students at
random and finds that 130 of them have a smart phone. In testing
the hypotheses: H 0 : p = 0.32 versus H a : p...

According to a Pew
Research Center study, in May 2011, 41% of all American adults had
a smart phone (one which the user can use to read email and surf
the Internet). A communications professor at a university believes
this percentage is higher among community college students. She
selects 378 community college students at random and finds that 162
of them have a smart phone. Then in testing the hypotheses:
H0: p = 0.41
versus
Ha: p > 0.41,
what...

According to a Pew Research Center study, in May 2011, 42% of
all American adults had a smart phone (one which the user can use
to read email and surf the Internet). A communications professor at
a university believes this percentage is higher among community
college students. She selects 420 community college students at
random and finds that 188 of them have a smart phone. Then in
testing the hypotheses:
H0: p = 0.42 versus
Ha: p > 0.42,
what...

According to a Pew Research Center study, in May 2011, 43% of
all American adults had a smart phone (one which the user can use
to read email and surf the Internet). A communications professor at
a university believes this percentage is higher among community
college students. She selects 405 community college students at
random and finds that 196 of them have a smart phone. Then in
testing the hypotheses:
H0: p = 0.43 versus
Ha: p > 0.43,
what...

According to a Pew Research Center study, in May 2011, 43% of
all American adults had a smart phone (one which the user can use
to read email and surf the Internet). A communications professor at
a university believes this percentage is higher among community
college students. She selects 281 community college students at
random and finds that 145 of them have a smart phone. Then in
testing the hypotheses:
H 0 : p = 0.43 versus
H a :...

According to a Pew Research Center study, in May 2011, 34% of
all American adults had a smart phone (one which the user can use
to read email and surf the Internet). A communications professor at
a university believes this percentage is higher among community
college students. She selects 339 community college students at
random and finds that 136 of them have a smart phone. In testing
the hypotheses: H 0 : p = 0.34 versus H a : p...

Living with parents: The Pew Research Center reported
that 36% of American Millennials (adults ages 18–31) still live at
home with their parents. A group of students wants to conduct a
study to determine whether this result is true for students at
their campus. They survey 300 randomly selected students at their
campus and determine that 43% of them still live at home with their
parents. With this data, they test the following hypotheses at the
5% significance level. The...

According to a Pew Research Center nationwide telephone survey
of American adults conducted by phone between March 15 and April
24, 2011, 75% of adults said that college education has become too
expensive for most people and they cannot afford it (Time, May 30,
2011). Suppose that this result is true for the 2011 population of
American adults. In a recent poll of 1575 American adults, 1150
said that college education has become too expensive for most
people and they...

Living with parents: The Pew Research Center reported that 36%
of American Millennials (adults ages 18–31) still live at home with
their parents. A group of students wants to conduct a study to
determine whether this result is true for students at their campus.
They survey 300 randomly selected students at their campus and
determine that 43% of them still live at home with their parents.
With this data, they test the following hypotheses at the 5%
significance level. The...

The auditor for a large corporation routinely monitors cash
disbursements. As part of this process, the auditor examines check
request forms to determine whether they have been properly
approved. Improper approval can occur in several ways. For
instance, the check may have no approval, the check request might
be missing, the approval might be written by an unauthorized
person, or the dollar limit of the authorizing person might be
exceeded.
(a) Last year the corporation experienced a 5
percent improper...

ADVERTISEMENT

Get Answers For Free

Most questions answered within 1 hours.

ADVERTISEMENT

asked 3 minutes ago

asked 5 minutes ago

asked 35 minutes ago

asked 37 minutes ago

asked 48 minutes ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 2 hours ago

asked 2 hours ago

asked 2 hours ago

asked 2 hours ago