3. A legislative aide doing research on the duration of calls initiated on cell phones. A preliminary study showed that the standard deviation is 1.7. "How large" a sample is needed for the aide to be able to state with 99% confidence the sample mean differs from the population mean by no more than 0.20 minutes.
Solution :
Given that,
standard deviation = =1.7
Margin of error = E = 0.20
At 99% confidence level the z is,
= 1 - 99%
= 1 - 0.99 = 0.01
/2 = 0.005
Z/2 = 2.576
sample size = n = [Z/2* / E] 2
n = ( 2.576* 1.7/ 0.20)2
n =479.43
Sample size = n =479
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