Days Absent |
Grade Level |
|||
E5 K to 6th |
E6 7th to 9th |
E7 10th & Above |
Total |
|
E1 >=10 days |
e1 10 |
e2 15 |
e3 25 |
50 |
E2 3 to 9 days |
e4 65 |
e5 55 |
e6 80 |
200 |
E3 1 to 2 days |
e7 75 |
e8 50 |
e9 25 |
150 |
E4 0 days |
e10 35 |
e11 45 |
e12 20 |
100 |
Total |
185 |
165 |
150 |
500 |
a)
Days Absent |
Grade Level |
|||
E5 K to 6th |
E6 7th to 9th |
E7 10th & Above |
Total |
|
E1 >=10 days |
e1 10 |
e2 15 |
e3 25 |
50 |
E2 3 to 9 days |
e4 65 |
e5 55 |
e6 80 |
200 |
E3 1 to 2 days |
e7 75 |
e8 50 |
e9 25 |
150 |
E4 0 days |
e10 35 |
e11 45 |
e12 20 |
100 |
Total |
185 |
165 |
150 |
500 |
The value given in the above table are frequencies of each Event and elementary event
b)
Probability (P) = Favourable Outcome (F) / Total Outcome (T)
Total Outcome = 500C1 = 500
E1 or E4 or both. Since both E1 and E4 cannot occur simultaneously
Favourable Outcome (F) = 50C1 + 100C1 =150
Hence P = 150/500 = 0.3
c)
E3 and E7 both occurring simultaneously
F = 25C1 =25
P = 25/500 = 0.05 or 5%
Elementary event e9 represents both events E3 and E7 occurring
d)
either event E3 or E7
F = 150C1 + 150C1 - 25C1 =275
P = 275/500 = 0.55 or 55%
e)
probability a student will miss 1 to 2 days, given the student is in the K-6th grade level
F = 75C1 =75
P = 75/500 = 0.15 or 15%
f)
probability a student will miss more than two days, given the student is in grade 10 or above?
F = 80C1 +25C1=105
P = 105/500 = 0.21 or 21%
Get Answers For Free
Most questions answered within 1 hours.