Question

An analyst for the superintendent’s office decides to examine the attendance of 500 randomly selected students...

  1. An analyst for the superintendent’s office decides to examine the attendance of 500 randomly selected students by their grade. Her data is shown in the table below:

Days Absent

Grade Level

E5

K to 6th

E6

7th to 9th

E7

10th & Above

Total

E1

>=10 days

e1

10

e2

15

e3

25

50

E2

3 to 9 days

e4

65

e5

55

e6

80

200

E3

1 to 2 days

e7

75

e8

50

e9

25

150

E4

0 days

e10

35

e11

45

e12

20

100

Total

185

165

150

500

  1. Compute the frequencies of each event and elementary event.
  2. What is the probability of either event E1 or E4, or both occurring?
  3. What is the probability of both events E3 and E7 occurring? Which elementary event(s) represents both events E3 and E7 occurring?
  4. What is the probability of either event E3 or E7 occurring?
  5. What is the probability a student will miss 1 to 2 days, given the student is in the K-6th grade level?
  6. What is the probability a student will miss more than two days, given the student is in grade 10 or above?

Homework Answers

Answer #1

a)

Days Absent

Grade Level

E5

K to 6th

E6

7th to 9th

E7

10th & Above

Total

E1

>=10 days

e1

10

e2

15

e3

25

50

E2

3 to 9 days

e4

65

e5

55

e6

80

200

E3

1 to 2 days

e7

75

e8

50

e9

25

150

E4

0 days

e10

35

e11

45

e12

20

100

Total

185

165

150

500

The value given in the above table are frequencies of each Event and elementary event

b)

Probability (P) = Favourable Outcome (F) / Total Outcome (T)

Total Outcome = 500C1 = 500

E1 or E4 or both. Since both E1 and E4 cannot occur simultaneously

Favourable Outcome (F) = 50C1 + 100C1 =150

Hence P = 150/500 = 0.3

c)

E3 and E7 both occurring simultaneously

F = 25C1 =25

P = 25/500 = 0.05 or 5%

Elementary event e9 represents both events E3 and E7 occurring

d)

either event E3 or E7

F = 150C1 + 150C1 - 25C1 =275

P = 275/500 = 0.55 or 55%

e)

probability a student will miss 1 to 2 days, given the student is in the K-6th grade level

F = 75C1 =75

P = 75/500 = 0.15 or 15%

f)

probability a student will miss more than two days, given the student is in grade 10 or above?

F = 80C1 +25C1=105

P = 105/500 = 0.21 or 21%

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