There are 32 chocolates in a box, all identically shaped. There 11 are filled with nuts, 13 with caramel, and 8 are solid chocolate. You randomly select one piece, eat it, and then select a second piece.
Find the following probabilities. Enter your answer in decimal notation, rounded to the nearest thousandth.
(a) The probability of selecting 2 solid chocolates in a row
(b) If the first was a solid chocolate, the probability that the second chocolate will be filled with caramel
(c) The probability of selecting a solid chocolate and a chocolate filled with caramel
(a)
Probability of selecting 2 solid chocolates in a row = Probability of selecting first solid chocolates (8 out of 32) * Probability of selecting second solid chocolates (7 out of 31)
= (8/32) * (7/31)
= 0.056
(b)
If the first was a solid chocolate, the probability that the second chocolate will be filled with caramel
= probability to pick caramel (13) out of remaining 31 chocolates
= 13/31
= 0.419
(c)
probability of selecting a solid chocolate and a chocolate filled with caramel =
Probability of selecting first solid chocolates (8 out of 32) * Probability of selecting second caramel chocolates (13 out of 31) + Probability of selecting first caramel chocolates (13 out of 32) * Probability of selecting second solid chocolates (8 out of 31)
= (8/32) * (13/31) + (13/32) * (8/31)
= (2 * 8 * 13) / (32 * 31)
= 0.210
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