Question

The combined SAT scores for the students at a local high school
are normally distributed with a mean of 1528 and a standard
deviation of 309. The local college includes a minimum score of 848
in its admission requirements.

What percentage of students from this school earn scores that fail
to satisfy the admission requirement?

*P*(*X* < 848) = %

Enter your answer as a percent accurate to 1 decimal place (do not
enter the "%" sign). Answers obtained using exact *z*-scores
or *z*-scores rounded to 3 decimal pl

Answer #1

Solution:

Let X be the combined SAT score for the students at local high school.

To find P( X < 848)

= P( Z < -2.200647)

= 1- P(Z > 2.20)

= 1 - 0.9861. From Z score

P( X < 848) = 0.0139

P( X < 848) = 0.014

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