Question

The combined SAT scores for the students at a local high school are normally distributed with a mean of 1528 and a standard deviation of 309. The local college includes a minimum score of 848 in its admission requirements.

What percentage of students from this school earn scores that fail to satisfy the admission requirement?
P(X < 848) =  %

Enter your answer as a percent accurate to 1 decimal place (do not enter the "%" sign). Answers obtained using exact z-scores or z-scores rounded to 3 decimal pl

Answer 1

Solution:

Let X be the combined SAT score for the students at local high school.

To find P( X < 848)

= P( Z < -2.200647)

= 1- P(Z > 2.20)

= 1 - 0.9861. From Z score

P( X < 848) = 0.0139

P( X < 848) = 0.014

1.4% of the students from this high school earn score that fail to satisfy the admission requirements.