The physical plant at the main campus of a large state university recieves daily requests to replace florecent lightbulbs. The distribution of the number of daily requests is bell-shaped and has a mean of 62 and a standard deviation of 8. Using the 68-95-99.7 rule, what is the approximate percentage of lightbulb replacement requests numbering between 54 and 62?
Solution :
Given that ,
mean = =62
standard deviation = = 8
P(54< x < 62) = P[(54 - 62) /8 < (x - ) / < (62 - 62 ) /8 )]
= P( -1< Z < 0)
= P(Z <-1)+P(Z <0 )
using empirical rule
=68%/2 + 0%/2
=34%+0%
=34%
38%approximate percentage of lightbulb replacement requests numbering between 54 and 62
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