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During a rock concert, the noise level (in decibels) in front row seats has a mean...

During a rock concert, the noise level (in decibels) in front row seats has a mean of 96 dB with a standard deviation of 7 dB. Without assuming a normal distribution, find the minimum percentage of noise level readings within 9 standard deviations of the mean.

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Answer #1

Given: During a rock concert, the noise level (in decibels) in front row seats has a mean of 96 dB with a standard deviation of 7 dB.

To find: the minimum percentage of noise level readings within 9 standard deviations of the mean.

We have to calculate the above without assuming a normal distribution. So, we have to calculate this using Chebyshev's Theorem

Chebyshev's Theorem: proportion of data lying within "K" SD's of the mean is at least

So, the minimum percentage of noise level readings within 9 standard deviations of the mean is given by-

  

Therefor , the minimum percentage of noise level readings within 9 standard deviations of the mean is 98.76 ...............( ANSWER)

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