The Turkish Grocer Mehmet sells seedless grapes from France at 4,99 €/kilo. A sample of seven bags contained the following numbers of grapes: 46, 35, 52, 34, 42, 48, 44. Compute the mean and median number of grapes in a bag. Verify that ∑(x-x_bar)=0
Bag No | Grapes | X - X bar | |
1 | 46 | 3 | |
2 | 35 | -8 | |
3 | 52 | 9 | |
4 | 34 | -9 | |
5 | 42 | -1 | |
6 | 48 | 5 | |
7 | 44 | 1 | |
Total | 301 | 0 | |
Mean = Total Grapes / No of Bags = 301 / 7 = 43 | |||
The sum of X - X bar = 0 as shown above..
Bag No | Grapes | |
4 | 34 | |
2 | 35 | |
5 | 42 | |
7 | 44 | Median |
1 | 46 | |
6 | 48 | |
3 | 52 |
The Bags are arranged in increasing order . The bag with the smallest number of grapes is at the top followed by the 2nd smallest and so on.. Now , in this case , there are odd number of Bags, which is 7.. So, the median will be ( n+1)/2 th bag , which is 4th bag. Therefore , the median is 44
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