Question

The Turkish Grocer Mehmet sells seedless grapes from France at 4,99 €/kilo. A sample of seven bags contained the following numbers of grapes: 46, 35, 52, 34, 42, 48, 44. Compute the mean and median number of grapes in a bag. Verify that ∑(x-x_bar)=0

Answer 1

	Bag No	Grapes	X - X bar
	1	46	3
	2	35	-8
	3	52	9
	4	34	-9
	5	42	-1
	6	48	5
	7	44	1
Total		301	0
	Mean = Total Grapes / No of Bags = 301 / 7 = 43

The sum of X - X bar = 0 as shown above..

Bag No	Grapes
4	34
2	35
5	42
7	44	Median
1	46
6	48
3	52

The Bags are arranged in increasing order . The bag with the smallest number of grapes is at the top followed by the 2nd smallest and so on.. Now , in this case , there are odd number of Bags, which is 7.. So, the median will be ( n+1)/2 th bag , which is 4th bag. Therefore , the median is 44

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