Question

The PMF below represents the probabilty of catching a fish

Number of fish(X)	0	1	2	3
Probabilty (X)	.35	.5	.10	.005

a- Calculate the probabilty that you catch at least 2 fish?

b- Calculate the probabilty that you catch no fish or three fish?

c-What is the expected number of fish you catch?

Answer 1

solution:-

Given that

No.of fish 0 1 2 3

probabilty (X) .35 .5 .10 .005

a) P(X 2) = P(X = 2) + P(X = 3) = 0.10 + 0.05 = 0.15

b) P(no fish or three fish) = P(no fish ) + P(three fish) - P(no fish and three fish)

= 0.35 + 0.05

= 0.40

c) Expected no. of fish you catch

No.of fish 0 1 2 3

probabilty (X) .35 .5 .10 .05

X.P(X) 0 .5 .2 .15

mean () = X.P(X)

= 0+ .5+ .2+ .15

= 0.85