The company produces Pollock portion in their facility bagged and labeled as ‘1 lb’. We have the following random weights sampled during weight test:
1.06, 1.02,0.97, 0.98, 1.02, 0.98, 1.10, 1.00, 1.02,1.05, 1.03, 1.03.
1. Describe the null and research hypotheses.
2. Compute an appropriate estimate and its standard error
3. Find a confidence interval.
4.Test the hypotheses.
5. Interpret and explain your result.
1. Describe the null and research hypotheses.
The hypothesis being tested is:
H0: µ = 1
Ha: µ ≠ 1
2. Compute an appropriate estimate and its standard error
1.02 | mean Data |
0.04 | std. dev. |
0.01 | std. error |
3. Find a confidence interval.
1.00 | confidence interval 95.% lower |
1.05 | confidence interval 95.% upper |
0.02 | margin of error |
4.Test the hypotheses.
1.00 | hypothesized value |
1.02 | mean Data |
0.04 | std. dev. |
0.01 | std. error |
12 | n |
11 | df |
2.021 | t |
.0683 | p-value (two-tailed) |
5. Interpret and explain your result.
The p-value is 0.0683.
Since the p-value (0.0683) is greater than the significance level (0.05), we fail to reject the null hypothesis.
Therefore, we can conclude that µ = 1.
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