Question

Given: k=5 where n for each group is 12 (ex. k1 n=12, k2 n=12... k5 n=12) so N=60

Sigma squared = 1.54 (Celcius) ^2 =variability within groups Level of significance= alpha= .05 (5%)

Question: what is the probability of Anova detecting a difference as small as 2.0(Celcius) between population means? Im just not sure how to do this without any sample data. I calculated v1=4 and v2=55 but i'm not quite sure how to even start this.

Answer 1

required answer of what is the probability of Anova detecting a difference as small as 2.0 between populatio mean=0.000132

Sigma squared =mse= 1.54

SE(difference)=sqrt(2*mse/n)=sqrt(2*1.54/12)=0.5066

t=difference/SE(difference)=2/0.5066=3.95

P(difference<2)=P(difference/SE(difference)=2/0.5066)=P(t<3.95)=0.000113

( using ms-excel=tdist(3.95,55,1)

following information has been generated with given data

source	df	ss	ms
between group	4
within group (error)	55	84.7	1.54
total	59

answered by: anonymous