Question

At Abraham Lincoln High School an achievement test is used for college placement. Counselors selected a simple random sample of 30 students from the school and scored their tests by hand before sending them in for computer processing. For this sample, top enclose x equals 525 comma space s equals 25 . Construct a 99% confidence interval for mu, the population mean score for Abraham Lincoln High School. Round your answer to one decimal place.

Answer #1

Solution :

t_{
/2,df} = 2.756

Margin of error = E = t_{/2,df}
* (s /n)

= 2.756 * (25 / 30)

Margin of error = E = 12.6

The 99% confidence interval estimate of the population mean is,

- E < < + E

525 - 12.6 < < 525 + 12.6

512.4 < < 537.6

(512.4 , 537.6)

At a college a popular achievement test is used for
advanced college placement. Counselors selected a
random sample of 100 students from the college and scored their
tests by hand before sending them in for computer
processing. For this sample, the mean was 525 and s =
25. A 99% confidence interval for the mean
is:
(460.6,
589.4) b) (518.56,
531.44) c) (520.1,
529.9) d) (476,
574)

Solve the following questions with proper answer
1. At a college a popular achievement test is used for advanced
college placement. Counselors selected a random sample of 16
students from the college and scored their tests by hand before
sending them in for computer processing. For this sample, the mean
was 520 and s = 20. Construct a 95% confidence interval for the
mean. Circle the correct answer
(A) (509.4, 530.6)
(B) (508.8, 531.2)
(C) (510.1, 530.0)
(D) (509.6, 530.4)...

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