Question

The combined SAT scores for the students at a local high school are normally distributed with a mean of 1471 and a standard deviation of 294. The local college includes a minimum score of 1706 in its admission requirements.

What percentage of students from this school earn scores that satisfy the admission requirement?
P(X > 1706) =  %

Enter your answer as a percent accurate to 1 decimal place (do not enter the "%" sign). Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.

Answer 1

Solution :

Given that ,

mean = = 1471

standard deviation = = 294

P(X > 1706) = 1 - P(x <1706 )

= 1 - P[(x- ) / < (1706 - 1471) /294 ]

= 1 - P(z <0.799 )

Using z table ( see the z value 0.799 in standard normal (z) table corresponding value is 0.7879 )

= 1 - 0.7879

=0.2121

percent=21.2