A sample of parts was taken from a population of finished parts that had U = 470, O=18. The sampling distribution for Xbar was found (using the CLT) to be normal with mean 470 and standard error 2. What was the sample size?
Solution :
Given that,
mean = = 470
standard deviation = = 18
= = 470
= 2
n = ( / )2
n = ( 18 / 2 )2
sample size = n = 81
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