given data are:-
sample size (n ) = 45
sample proportion () = 60% = 0.6
hypothesis:-
level of significance () = 0.10
the test statistic is :-
p value is :-
[ in any blank cell of excel type =NORMSDIST(0.8076)]
conclusion:-
p value = 0.2097 > 0.10 (alpha)
so, we fail to reject the null hypothesis and conclude that there is not sufficient evidence to claim that the percent of adults who consume three servings of dairy products greater than 54%.
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