Question

The Gallup Poll asked 1,015 U.S. adults whether they believed that people should pay sales tax...

The Gallup Poll asked 1,015 U.S. adults whether they believed that people should pay sales tax on items purchased over the internet. Of these, 437 said they supported such a tax. does the survey provide evidence that less than 46% of U.S. adults favor an internet sales tax? Use the alpha= 0.05 level. State hypotheses Verify conditions are met Find the value of the test statistic Identify the P-value State decision Conclusion in non-statistical terms

Homework Answers

Answer #1

Given : n=1015 , X=437 , The estimate of the sample proportion is ,

Now , and

Therefore , use the one sample proportion Z-test.

Hypothesis: Vs  

The test statistic is ,

The p-value is ,

p-value=

; From standard normal distribution table

Decision : Here ,p-value=0.0294 < 0.05

Therefore , reject Ho

Conclusion : Hence , there is sufficient evidence to support the claim that the less than 46% of U.S. adults favor an internet sales tax.

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
The Gallup Poll asked 500 U.S. adults whether they believed that people should pay sales tax...
The Gallup Poll asked 500 U.S. adults whether they believed that people should pay sales tax on items purchased over the Internet. Of these, 180 said they supported such a tax. Does the survey provide convincing evidence that less than 39% of U.S. adults favor an Internet sales tax? Use p-value method and 0.01 significance level.
In 2013, the Gallup Poll asked 1031 U.S. adults whether they believed that people should pay...
In 2013, the Gallup Poll asked 1031 U.S. adults whether they believed that people should pay sales tax on items purchased over the internet. Of these, 443 said they supported such a tax. Does the survey provide convincing evidence that less than 45% of U.S. adults favor an internet sales tax? Use the α=0.05 level of significance and the P-value method with the TI-84 Plus calculator. a. state null and alternative hypothesis. what tail is the hypothesis test? b. Compute...
Question 23: Internet tax: In 2013 , the Gallup Poll asked 1019 U.S . adults whether...
Question 23: Internet tax: In 2013 , the Gallup Poll asked 1019 U.S . adults whether they believed that people should pay sales tax on items purchased over the internet. Of these, 428 said they supported such a tax. Does the survey provide convincing evidence that more than 39% of U.S. adults favor an internet sales tax? Use the =α0.05 level of significance and the P -value method with the TI-84 Plus calculator. Part: 0 / 4 0 of 4...
Section 9.4 Question 3 of 7 Internet tax: In 2013, a consulting company asked 1017 U.S....
Section 9.4 Question 3 of 7 Internet tax: In 2013, a consulting company asked 1017 U.S. adults whether they believed that people should pay sales tax on items purchased over the Internet. Of these, 397 said they supported such a tax. Does the survey provide convincing evidence that more than 38% of U.S adults favor an Internet sale tax? Use the α=0.01 level of significance and the critical value method. 1. Null and Alternate Hypotheses? 2. Critical Value? 3.Test Statistic?...
A telephone poll of 750 adults was taken. The question asked was: “Should the federal tax...
A telephone poll of 750 adults was taken. The question asked was: “Should the federal tax on cigarettes be raised to pay for health care reform?” Of the 502 nonsmokers, 300 said yes. Of the 248 smokers, 50 said yes. At á = 0.05, test the claim that the proportion of nonsmokers in favor of the federal tax is greater than the proportion of smokers in favor of the tax.
Gallup poll consisted of 1012 randomly selected adults who were asked whether or not cloning of...
Gallup poll consisted of 1012 randomly selected adults who were asked whether or not cloning of humans should be allowed. 901 of the adults surveyed said that cloning should not be allowed. Construct a 98% confidence interval to estimate the true percentage of all adults who hold this belief. 1. State the Parameter 2. Find the point estimate 3. Check assumptions 4.Find the critical value 5. Find the margin of error 6. Find the confidence interval limits
A recent Gallup Poll asked a random sample of 1785 adults, “Did you attend church or...
A recent Gallup Poll asked a random sample of 1785 adults, “Did you attend church or synagogue in the last seven (7) days?” Of the respondents, 750 said “Yes.” The National Association of Churches and Synagogues detailed that fewer than 45% of adults have attended a church or synagogue in the last seven (7) days. Assume a 95% confidence level. Provide the following in your final analyses: the distribution to be used and why; all assumptions required for this study...
A recent survey was conducted and the main question asked was "Do you think the use...
A recent survey was conducted and the main question asked was "Do you think the use of marijuana should be made legal, or not?" The poll results are summarized below. Response Count Yes 558 No 367 Undecided 90 At the 1% significance level, do these poll results provide sufficient evidence to support the claim that a majority (i.e., more than half) of U.S. residents are in favor of legalizing marijuana? 1. Define the parameter of interest and state the null...
Assume that adults were randomly selected for a poll. They were asked if they​ "favor or...
Assume that adults were randomly selected for a poll. They were asked if they​ "favor or oppose using federal tax dollars to fund medical research using stem cells obtained from human​ embryos." Of those​ polled, 483 were in​ favor, 405 were​ opposed, and 123 were unsure. A politician claims that people​ don't really understand the stem cell issue and their responses to such questions are random responses equivalent to a coin toss. Exclude the 123 subjects who said that they...
13. A 2007 Gallup poll randomly sampled 1019 people, and asked them how long it took...
13. A 2007 Gallup poll randomly sampled 1019 people, and asked them how long it took them to commute to work each day. The sample mean one-way commute time was 22.8 minutes with a standard deviation of 17.9 minutes. A transportation engineer claims that the mean commute time is greater than 20 minutes. Do the data provide convincing evidence that the engineer’s claim is true? Use the α = .05 level of significance. a. Check the conditions. b. State the...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT