Question

Suppose that an urn contains 8 red balls and 4 white balls. We draw 2 balls...

Suppose that an urn contains 8 red balls and 4

white balls. We draw 2 balls

from the urn without replacement.

Now suppose that the balls have

different weights, with each red ball having weight

r and each white ball having weight w. Suppose that the probability that a given ball in

the urn is the next one selected is its weight divided by the sum of the weights of all

balls currently in the urn.

Now what is the probability that both balls are red?

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