Question

Find the 99% confidence interval for estimating
*μ*_{d} based on these paired data and assuming
normality. (Give your answers correct to one decimal place.)

Before | 42 | 65 | 52 | 57 | 58 | 48 |

After | 30 | 43 | 48 | 32 | 30 | 50 |

Lower Limit | |

Upper Limit |

Answer #1

Before | After | Difference |

42 | 30 | 12 |

65 | 43 | 22 |

52 | 48 | 4 |

57 | 32 | 25 |

58 | 30 | 28 |

48 | 50 | -2 |

Sample mean if the difference, x̅_{d} =
14.8333

Sample standard deviation of the difference, s_{d}
= 12.1395

Sample size, n = 6

**99% Confidence interval for the differnce:
**

At α = 0.01, and df = 5, two tailed critical value, t-crit = T.INV.2T(0.05 , 5 ) = 4.032

Lower Bound = x̅_{d} -
t-crit*s_{d}/√n = **-5.1**

Upper Bound = x̅_{d} + t-crit*s_{d}/√n =
**34.8**

Find the 95% confidence interval for estimating μd based on
these paired data and assuming normality. (Give your answers
correct to one decimal place.) Before 43 42 67 54 59 55 After 42 50
34 54 30 58 Lower Limit Upper Limit

Find the 99% confidence interval for the difference between two
means based on this information about two samples. Assume
independent samples from normal populations. (Use conservative
degrees of freedom.) (Give your answers correct to two decimal
places.)
Sample
Number
Mean
Std. Dev.
1
25
30
32
2
12
25
24
Lower Limit
Upper Limit

Find the 99% confidence interval for the difference between two
means based on this information about two samples. Assume
independent samples from normal populations. (Use conservative
degrees of freedom.) (Give your answers correct to two decimal
places.) Sample Number Mean Std. Dev. 1 11 39 34 2 23 25 22 Lower
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Age of CEO
57
49
57
63
58
56
67
62
61
61
53
58
52
58
56
66
56
59
52
63
52
59
57
64
53
54
65
46
58
58
57
50
62
57
58
52
48
59
54
62
66
46
52
63
57
52
61
50
55
55
64
48
56
58
55
60
51
62
62
50
45
50
52
55
58
57
52
53
61
55
63
54
52
59
50
56
57...

Using techniques from an earlier section, we can find a
confidence interval for μd. Consider a
random sample of n matched data pairs A,
B. Let d = B − A be a random
variable representing the difference between the values in a
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differences and the sample standard deviation
sd. If d has a normal distribution or
is mound-shaped, or if n ≥ 30, then a confidence
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x overbarx=15
s=5.6
n=12
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The pulse rates for 13 adult women were as follows. Construct a
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96
63
84
69
71
108
95
57
85
102
105
79
92
Lower limit
Upper limit

Using techniques from an earlier section, we can find a
confidence interval for μd. Consider a
random sample of n matched data pairs A,
B. Let d = B − A be a random
variable representing the difference between the values in a
matched data pair. Compute the sample mean
d
of the differences and the sample standard deviation
sd. If d has a normal distribution or
is mound-shaped, or if n ≥ 30, then a confidence
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find a 95% confidence interval for the mean electricity
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find a 95% prediction interval for the electricity consumption for a new
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temperatureavg kilowattsperhour
77.5 45
80 73
78 43
78.5 61
77.5 52
83 56
83.5 70
81.5 70
75.5 53
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70 39
73.5 55
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