Determine the sample size needed to obtain an estimate of µ if the margin of error E = 0.06, σ = 0.75, and the confidence level is 99%
a) Find α for 99% confidence
level.
α =
(b) Find 1 − α/2.
1 − α/2 =
(c) Find zα/2 for a
99% confidence level.
zα/2 =
Solution :
Given that,
standard deviation = =0.75
Margin of error = E = 0.06
At 99% confidence level the z is,
= 1 - 99%
= 1 - 0.99 = 0.01
/2 = 0.005
Z/2 = 2.576
sample size = n = [Z/2* / E] 2
n = ( 2.576*0.75 / 0.06 )2
n =1036.84
Sample size = n =1037
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