Question

In a large sample study according to a report by the U.S.surgeon general, electrical engineers have...

In a large sample study according to a report by the U.S.surgeon general, electrical engineers have the lowest smoking rate among all workers surveyed. Only 16% of the male electrical engineers in the sample smoke cigarettes regularly. How many male electrical engineers must be sampled to estimate the proportion of fall male electrical engineers who smoke regularly to within 3% of its true value with 95% confidence?

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
In order to determine if smoking causes cancer, researchers surveyed a large sample of adults. For...
In order to determine if smoking causes cancer, researchers surveyed a large sample of adults. For each adult they recorded whether the person had smoked regularly at any period in their life and whether the person had cancer. They then compared the proportion of cancer cases in those who had smoked regularly at some time in their lives with the proportion of cases in those who had never smoked regularly at any point in their lives. The researchers found a...
A report states that 44% of home owners had a vegetable garden. How large a sample...
A report states that 44% of home owners had a vegetable garden. How large a sample is needed to estimate the true proportion of home owners who have vegetable gardens to within 6% with 95% confidence? A. 132 B. 66 C. 263 D. 526
.1) How large a sample must one take to be 90% confident that the estimate is...
.1) How large a sample must one take to be 90% confident that the estimate is within 5% of the true      proportion of women over 55 who are widows?  A recent study indicated that 29% of the 100 women      over 55 in the study were widows. 8.  As a manufacturer of golf equipment, the Spalding Corporation wants to estimate the proportion of      golfers who are left-handed.  (The company can use this information in planning for the number of      right-handed and left-handed sets of...
According to a union agreement, the mean income for all senior-level assembly-line workers in a large...
According to a union agreement, the mean income for all senior-level assembly-line workers in a large company equals $490 per week. A representative of a women's group decides to analyze whether the mean income for female employees matches this norm. For a random sample of nine female employees, using software, she obtains a 95% confidence interval of (464 ,498 ). Explain what is wrong with each of the following interpretations of this interval. Complete parts a through d below.a. We...
According to the Oxnard College Student Success Committee report in the previous year, we believe that...
According to the Oxnard College Student Success Committee report in the previous year, we believe that 21% of students struggle in their classes because they don't spend more than 8 hours studying independently outside of a 4-unit class. For this year, you would like to obtain a new sample to estimate the proportiton of all Oxnard students who struggle in their classes because they don't study enough outside of the classrooms. You would like to be 99% confident that your...
1. In a study of academic procrastination, it was determined that for a random sample of...
1. In a study of academic procrastination, it was determined that for a random sample of 16 undergrad students at a mid-size public university, the mean time spent studying for the final quiz in an intro statistics course was 7.74 hours with a standard deviation of 3.40 hours. Suppose we wish to compute a 95% confidence interval for the mean time spent studying for the intro statistics final quiz by all students. The margin of error for this confidence interval...
There was concern among health officials in the Windham area that an unusually large percentage of...
There was concern among health officials in the Windham area that an unusually large percentage of newborn babies had abnormally low birth weights (less than 5.5 lbs.). A sample of 250 newborns showed 20 of these babies had abnormally low birth weight. Construct a 95% confidence interval for the true proportion of babies in the Windham area who have abnormally low birth weight. a. .10 ± .042 b. .10 ± .042 c.   .08 ± .028 d. .08 ± .034 e....
The 2010 General Social Survey asked 1208 US residents: "Do you think the use of marijuana...
The 2010 General Social Survey asked 1208 US residents: "Do you think the use of marijuana should be made legal, or not?" Of the respondents, 585 said it should be made legal. 1. The value 48.43% is a... A. sample statistic B. population parameter 2. Construct a 95% confidence interval for the proportion of US residents who think marijuana should be made legal, and interpret it in the context of the data. Round your results to four decimal places. (...
According to a recent article, 32% of drivers had driven drowsy in the past month. (Source:...
According to a recent article, 32% of drivers had driven drowsy in the past month. (Source: Thenationshealth.aphapublications.org/content/41/10/E52.fuII) Suppose law enforcement officials are planning a survey of 1000 drivers to determine what proportion are driving drowsy. A. Is whether a driver has driven drowsy in the past month qualitative or quantitative? B. Would it be unusual if, in a random sample of 1000 drivers, 35% or more were driving drowsy in the last month? Include justifications for full credit. C. What...
In a study of health behavior, a random sample of 500 subjects from a major city...
In a study of health behavior, a random sample of 500 subjects from a major city was surveyed. In this random sample, 310 responded that they had dinner mostly after 8 PM. At 5% level of significance, does the data support that more than 60% of the residents in this city had dinner after 8 PM? (Must state null and alternative hypotheses and use p-value to conclude the test. You can use Chi-square Goodness of fit test or Binomial test...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT