Question

Canadian Dial Up, an online service provider, wants to know if more than 70% of their customers spend at least 10 hours per week working online. They conducted a survey of 250 of their customers and found that 141 of them spend at least 10 hours per week working online. Test the claim using α=0.10.

Answer 1

Solution :

The null and alternative hypothesis is

H0 : p = 0.70

Ha : p > 0.70

= x / n = 141 / 250 = 0.564‬

1 - P0 = 0.30

Test statistic = z

= - P0 / [P0 * (1 - P0 ) / n]

= 0.564‬ - 0.70 / [(0.70 * 0.30) / 250]

= -4.69

P-value = 1

= 0.10

P-value >

Fail to reject the null hypothesis .

There is no sufficient evidence to support the claim.