Question

In an early home game, an NBA team made 72.34 percent of their 94 free throw...

In an early home game, an NBA team made 72.34 percent of their 94 free throw attempts. In one of their last home games, the team had a free throw percentage equal to 78.16 percent out of 87 attempts. Do basketball teams improve their free throw percentage as their season progresses? Test the appropriate hypotheses for free throw percentages, treating the early season and late season games as random samples. Use a level of significance of .10.

(a-1)

Assume ππ1 is the early proportion of free throws and ππ2 is the later proportion. Choose the correct null and alternative hypotheses.

a. H0: ππ1 – ππ2 ≤ 0 vs. H1: ππ1 – ππ2 > 0
b. H0: ππ1 – ππ2 = 0 vs. H1: ππ1 – ππ2 ≠ 0
c. H0: ππ1 – ππ2 ≥ 0 vs. H1: ππ1 – ππ2 < 0
a
b
c
(b-1) Use Excel to calculate the exact p-value. (Round the number of free throws to the nearest integer; and round your answer to 4 decimal places.)
  p-value   

Homework Answers

Answer #1

The statistical software output for this problem is:

Hence,

a - 1) H0: ππ1 – ππ2 ≥ 0 vs. H1: ππ1 – ππ2 < 0

b - 1) p - Value = 0.1827

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Sue, a starting player for a major college basketball team, made only 38% of her free...
Sue, a starting player for a major college basketball team, made only 38% of her free throws last year. During the summer she worked on developing a softer shot in the hope of improving her free-throw accuracy. In the first eight games of this season Sue made 22 free throws in 40 attempts. Assume that these 40 attempts represent a random sample of free throws. Let p be the probability of making each free throw she shoots this season. Does...
A professional basketball star who had a reputation for being a poor free throw shooter made...
A professional basketball star who had a reputation for being a poor free throw shooter made 5051 of the 9807 free throws that he​ attempted, for a success ratio of 0.515 A simulation was developed to generate random numbers between 1 and 1000. An outcome of 1 through 515515 was considered to be a free throw that is​ made, and an outcome of 516 through 1000 was considered to be a free throw that is missed. The list below shows...
Since the mid-1960s, the overall free throw percent at all college levels, for both men and...
Since the mid-1960s, the overall free throw percent at all college levels, for both men and women, has remained pretty consistent. For men, players have shot roughly 69% with the season percent never falling below 67% or larger than 70%. Assume that 300,000 free throws will be attempted in the upcoming season. Fill in the blanks. If the population proportion, p = 0.69, The mean, μμ, of X is ------- The standard deviation, σσ, of X is (round to 4...
During the first 20 games of a basketball season, one player made 34 of her 40...
During the first 20 games of a basketball season, one player made 34 of her 40 free throws. A teammate made 35 of her 44 free throws. Assume that all conditions for running two proportion inference procedures have been met - even though this is questionable. a) determine the two different standard errors you would use for the following procedures. -Confidence interval -test of significance b) The 95% confidence interval for the difference in the two proportions (player-teammate) is about...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT