Complete the following ANOVA summary table. There are seven
groups of plants receiving different fertilizer treatments, each
with 24 samples. Use a significance level of α=0.10
Source | SS | df | MS | F | P |
---|---|---|---|---|---|
Between | 124.875 | ||||
Within | |||||
TOTAL | 1511.085 |
Given
K = 7 group of plant
n = 7*24 = 168
SS Between = 124.875
SS TOTAL = 1511.085
1) now calculate ss within
SS WITHIN = SS TOTAL - SS BETWEEN
= 1511.085 - 124.875
SS WITHIN = 1386.21
2) now calculate df
DF OF BETWEEN = K-1 = 7-1 = 6
DF OF WITHIN = n - k = 168-7 = 161
Df total = n-1 = 168 - 1 =167
3) MSSB= SS BETWEEN /DF OF SS
= 124.875/6
MSSB = 20.8125
MSSW = SS within /df within
= 1386.21/161
MSSW = 8.61
4) F = MSSB/MSSW
= 20.8125/8.61
F = 2.417
5) p value is 0.0290
P value = 0.0290
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