Question

Here is data on the number of days required for fruit maturation. (a) Enter the following...

Here is data on the number of days required for fruit maturation.

(a) Enter the following data in R data <- c(26,24,29,33,25,26,23,30,31,30,28,27,29,26,28)(26,24,29,33,25,26,23,30,31,30,28,27,29,26,28)

(b) Test the hypothesis that the mean is equal to 29.5 days.

(c). Would this be a 1 tailed or 2 tailed, why?

(d). State the null and alternative hypotheses?

(e). Interpret the test results

(f). What null distribution did you use

Homework Answers

Answer #1

(a-b)

Following is the screen shot of R:

Following is the output:

(c)

Test is two tailed.

(d)

Hypotheses are:

(e)

The p-value is 0.02145

Since p-value is less than 0.05 so we reject the null hypothesis. That is we cannot conclude that the mean is equal to 29.5 days.

(f)

t-distribution with df= 14

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Real Fruit Juice (Raw Data, Software Required): A 32 ounce can of a popular fruit drink...
Real Fruit Juice (Raw Data, Software Required): A 32 ounce can of a popular fruit drink claims to contain 20% real fruit juice. Since this is a 32 ounce can, they are actually claiming that the can contains 6.4ounces of real fruit juice. The consumer protection agency samples 30 such cans of this fruit drink. The amount of real fruit juice in each can is given in the table below. Test the claim that the mean amount of real fruit...
Real Fruit Juice (Raw Data, Software Required): A 32 ounce can of a popular fruit drink...
Real Fruit Juice (Raw Data, Software Required): A 32 ounce can of a popular fruit drink claims to contain 20% real fruit juice. Since this is a 32 ounce can, they are actually claiming that the can contains 6.4 ounces of real fruit juice. The consumer protection agency samples 30 such cans of this fruit drink. The amount of real fruit juice in each can is given in the table below. Test the claim that the mean amount of real...
Real Fruit Juice (Raw Data, Software Required): A 32 ounce can of a popular fruit drink...
Real Fruit Juice (Raw Data, Software Required): A 32 ounce can of a popular fruit drink claims to contain 20% real fruit juice. Since this is a 32 ounce can, they are actually claiming that the can contains 6.4 ounces of real fruit juice. The consumer protection agency samples 30 such cans of this fruit drink. The amount of real fruit juice in each can is given in the table below. Test the claim that the mean amount of real...
Question 1: The data table shows the sugar content of a fruit (Sugar) for different numbers...
Question 1: The data table shows the sugar content of a fruit (Sugar) for different numbers of days after picking (Days). Days Sugar 0 7.9 1 12.0 3 9.5 4 11.3 5 11.8 6 10.3 7 4.2 8 0.8 HAND CALCULATIONS: The dependent (Y) variable is sugar content and the independent (X) variable is number of days after picking (Days). Do the following by hand, SHOWING WORK. You may use SAS/R to check your answers if you want. (a) Find...
a) Identify the claim: state the null and alternative hypotheses. b) Determine the test: left-tailed, right-tailed,...
a) Identify the claim: state the null and alternative hypotheses. b) Determine the test: left-tailed, right-tailed, or two-tailed. c) Graph your bell-shaped curve and label your levels of significance or critical value. d) Find your standardized test statistic ? and label it on your graph. e) Decide whether to reject or fail to reject the null hypothesis. f) Interpret your result. A study was conducted to determine if the salaries of elementary school teachers from two neighboring states were equal....
No data required. Enter in the inferential test that should be run to answer the research...
No data required. Enter in the inferential test that should be run to answer the research question: Z-Test, One-Sample t-Test, Independent t-Test, Paired t-Test, or ANOVA (NOTE: not all tests may be used in this assignment. Read the questions carefully.). Write your Null and Alternative Hypothesis as a full sentence. 1. Is there a difference in the ages of people based on the amount of time they work per week? Inferential Test: Null Hypothesis (H0): Alternative Hypothesis (H1): Should the...
It is believed that nearsightedness affects 8 % of children. In a Random Sample of 194...
It is believed that nearsightedness affects 8 % of children. In a Random Sample of 194 children, 21 are nearsighted. Does the data prove that 8% is an inaccurate value? Use 1% level of significance. A. State the null Hypotheses B State the alternative hypotheses C. One or Two Tail Test? D. State the critical Value of the hypothesis test. E. Illustrate the rejection region using a graph. F. What is the test Statistic? G. What is the P value...
Real Fruit Juice: A 32 ounce can of a popular fruit drink claims to contain 20%...
Real Fruit Juice: A 32 ounce can of a popular fruit drink claims to contain 20% real fruit juice. Since this is a 32 ounce can, they are actually claiming that the can contains 6.4 ounces of real fruit juice. The consumer protection agency samples 44 such cans of this fruit drink. Of these, the mean volume of fruit juice is 6.32 with standard deviation of 0.23. Test the claim that the mean amount of real fruit juice in all...
A 32 ounce can of a popular fruit drink claims to contain 20% real fruit juice....
A 32 ounce can of a popular fruit drink claims to contain 20% real fruit juice. Since this is a 32 ounce can, they are actually claiming that the can contains 6.4 ounces of real fruit juice. The consumer protection agency samples 46 such cans of this fruit drink. Of these, the mean volume of fruit juice is 6.35 with standard deviation of 0.21. Test the claim that the mean amount of real fruit juice in all 32 ounce cans...
Real Fruit Juice: A 32 ounce can of a popular fruit drink claims to contain 20%...
Real Fruit Juice: A 32 ounce can of a popular fruit drink claims to contain 20% real fruit juice. Since this is a 32 ounce can, they are actually claiming that the can contains 6.4 ounces of real fruit juice. The consumer protection agency samples 42 such cans of this fruit drink. Of these, the mean volume of fruit juice is 6.34 with standard deviation of 0.21. Test the claim that the mean amount of real fruit juice in all...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT