A certain type of stainless steel powder is supposed to have a mean particle diameter of μ = 15 μm. A random sample of 86 particles had a mean diameter of 15.2 μm, with a standard deviation of 1.8 μm. A test is made of H0 : μ = 15 versus H1 : μ ≠ 15.
Find the P-value. Round the answer to four decimal places.
Numeric Response
SOLUTION
this is the two tailed test .
The null and alternative hypothesis is ,
H0 : = 15
Ha : 15
Test statistic = z
= ( - ) / / n
= (15.2-15) / 1.8 / 86
= 1.03
P(z >1.03 ) = 1 - P(z < 1.03 ) = 1-0.8485=0.1515 USING Z TABLE
P-value =0.1515
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