hours spent studying x | 1 | 1 | 2 | 4 | 5 | 5 |
tet score y | 40 | 42 | 51 | 48 | 61 | 67 |
find the equation of the regression line for the given data. Then use the regression equation to predict the value of y for each of the given x values, if meaningful. The number of hours 6 students spent for a test and their scores are shown. a.) x = 2hours b.) x= 4.5 hours c.) x = 15 hrs d.) x = 1.5 hrs Find the regression equation y (hat) =__x +(__) (Round the slope to three decimal places as needed . Round the y intercept to two decimal places as needed. Predict the value of y for x =2. a.) 46.6 b.) 44.1 c.) 58.9 d.) not meaningful Predict the value of of y for x = 4.5. a.) 110.8 b.) 58.9 c.) 44.1 d.) not meaningful. Predict the value of y for x = 15. a.) 46.6 b,) 110.8 c.) 58.9 d.) not meaningful. Predict the value of y for x = 1.5 a.) 46.6 b.) 110.8 c.) 44.1 d.) not meaningful
Consider
Y : test Score.
X : Number of hours spends for study.
The regression equation Y on X is
Y = a + b X
where a is Y-intercept and b is slope of the regression line.
The estimated value of a and b is
x | y | (x-xbar) | (y-ybar) | (x-xbar)*(y-ybar) | (x-xbar)^2 |
1 | 40 | -2 | -11.5 | 23 | 4 |
1 | 42 | -2 | -9.5 | 19 | 4 |
2 | 51 | -1 | -0.5 | 0.5 | 1 |
4 | 48 | 1 | -3.5 | -3.5 | 1 |
5 | 61 | 2 | 9.5 | 19 | 4 |
5 | 67 | 2 | 15.5 | 31 | 4 |
18 | 309 | 0 | 0 | 89 | 18 |
Hence the line of regression Y on X is
Y = 4.944X + 36.67.
Value of slope = 4.944 and Y-intercept = 36.67
Predicted value of Y for diffrent value of X is
X | Predicted value of Y | Correct Answer |
2 | 46.558 | a- 46.6 |
4.5 | 58.918 | b- 58.9 |
15 | 110.83 | b- 110.8 |
1.5 | 44.086 | c- 44.1 |
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