Given a normal distribution with Mean of 100 and Standard deviation of 10, what is the probability that
between what two X values (symmetrically distributed around the mean) are 80% of the values?
Mean= 100
Std= 10
Data will be distributed equally on both sides of the mean. mean= 0.5
So, the probability is divided by 2 = 0.8/2 =0.4
Minimum value:
Where Z(0.1) = -1.282
Maximum value:
Z(0.9)= 1.282
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