There are 71 students in a nutrition class. The instructor must choose two students at random.
Academic Year | Nutrition majors | non-Nutrition majors |
---|---|---|
Freshmen | 17 | 5 |
Sophomores | 4 | 5 |
Juniors | 17 | 16 |
Seniors | 3 | 4 |
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What is the probability that a senior Nutrition major and then a sophomore Nutrition major are chosen at random? Express your answer as a fraction or a decimal number rounded to four decimal places.
Total number of students in nutrition class = 71
We need to find the probability that on random selection from these students, first a senior Nutrition major and then a sophomore Nutrition major are chosen.
From the table observe that there are 3 senior Nutrition majors and 4 sophomore Nutrition majors.
So first, the probability of selecting a senior Nutrition major = 3/71 then there are rest 70 students left in the class from which we have 4 options to choose so 4/70
Hence , probability that on random selection from these students, first a senior Nutrition major and then a sophomore Nutrition major are chosen = (3/71) x (4/70) = 12/4970 = 0.002414486922 = 0.0024 (rounded to four decimal places)
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