t critical value at 0.05 level with 1014 df = 1.962
95% confidence interval for is
- t * S / sqrt(n) < < + t * S / sqrt(n)
14.6 - 1.962 * 16.6 / sqrt(1015) < < 14.6 + 1.962 * 16.6 / sqrt(1015)
13.58 < < 15.62
95% CI is ( 13.58 , 15.62 )
Get Answers For Free
Most questions answered within 1 hours.