In a random sample of
88
people, the mean commute time to work was
36.536.5
minutes and the standard deviation was
7.27.2
minutes. A
9898%
confidence interval using the t-distribution was calculated to be
left parenthesis 28.9 comma 44.1 right parenthesis(28.9,44.1).
After researching commute times to work, it was found that the population standard deviation is
8.78.7
minutes. Find the margin of error and construct a
9898%
confidence interval using the standard normal distribution with the appropriate calculations for a standard deviation that is known. Compare the results.
The margin of error of
muμ
is
nothing.
(Round to two decimal places as needed.)
There is two more parts to this question that I cannot view yet.
given data are:-
z critical value for 98% confidence level, both tailed test be:-
the margin of error be:-
the 98% confidence interval be:-
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