Question

suppose that, on average, a salesman successfully makes a sale 34% of the time. Find the probability that in 55 attempts the same salesman makes more than 10 successful sales. Round to the nearest hundredth

Answer 1

Solution :

Given that,

Using binomial distribution,

= n * p = 0.34 * 55 = 18.7

= n * p * q = 55 * .34 * 0.66 = 3.5131

Using continuity correction ,

P(x > 10.5) = 1 - P(x < 10.5)

= 1 - P((x - ) / < (10.5 - 18.7) / 3.5131)

= 1 - P(z < 2.33)

= 0.9901

Probability = 0.990