(a)
For 6 students without any restriction:
Number of different arrangements is given by:
So,
Answer is :
120
(b)
If Anna and Kelly must sit together, consider Anna and Kelly as a single student.
So,
we get:
Number of different arrangements is given by:
Now Anna and Kelly can be permuted in 2! = 2 ways.
So,
Number of different arrangements with Anna and Kelly together is given by:
24 X 2= 48
So,
Answer is :
48
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