Question

While conducting a one-way ANOVA comparing 4 treatment samples with 5 observations per treatment sample, computed value for SS(Total) = 66 and MS(Error) = 3 given.

Source
of
Variation |

Treatment .…. …. ….. …… Error 48 …. 3 |

Total 66 |

What is the value of F-test statistic using ANOVA table?

6 |
||

2 |
||

3 |
||

5 |

Answer #1

While conducting a one-way ANOVA comparing 6 treatments with 10
observations per treatment, the computed value for
SS(Treatment)= 36, and SS(Error)=24. Calculate the value of
F.
Round off the answer to 2 decimal digits.

While conducting a one-way ANOVA comparing 6 treatments with 10
observations per treatment, computed value for SST = 290 and MSE =
5. Find the value of F and also construct the ANOVA
table.

Consider the partial ANOVA table shown below. Let a = .01
Source of Variation
DF
SS
MS
F
Between Treatments
3
180
Within Treatments (Error)
Total
19
380
If all the samples have five observations each:
there are 10 possible pairs of sample means.
the only appropriate comparison test is the Tukey-Kramer.
all of the absolute differences will likely exceed their
corresponding critical values.
there is no need for a comparison test – the null hypothesis is
not rejected.
2...

Consider the partially completed one-way ANOVA summary
table.
Source
SS
df
MS
F
Treatment
150
Error
17
Total
840
21
Using α = 0.05, the critical F-score for this ANOVA procedure
is ________.

The summary for a one-way ANOVA is given below:
Source of Variation
SS
df
MSS
F
Treatment
……..
…….
…….
……
Error
80
8
…….
Total
428
11
Complete the missing values in the table.
Write the null and alternative hypothesis.
How may treatments are in this study? What is the number of
observations in this study?
Knowing that the critical value is 4.07, our decision would
be………………………

4. To compare the means of 5 populations, random samples of size
10 are selected from each population. A partial ANOVA table for
this data is as follows: Source df SS MS F Treatment 15.32 Error
0.64 Total a. Fill in the missing entries in the ANOVA table. b.
Compute the pooled estimate of the population standard deviation.
c. State the null and alternative hypotheses in the experiment. d.
Test the hypotheses in part c). Use α=0.05.

A researcher conducts a two-way ANOVA test with interaction and
provides the following ANOVA table.
a.
Find the missing values in the
ANOVA table. (Round your answers to 2 decimal
places.)
ANOVA
Source of
Variation
SS
df
MS
F
p-value
F
crit
Sample
766.98
2
MSB
=
Ffactor B =
0.0109
3.885
Columns
12,122.69
1
MSA
=
Ffactor A =
0
4.747
Interaction
57.60
2
MSAB
=
FInteraction =
0.6148
3.885
Within
682.14
12
MSE
=
Total
13,629.41
17

1. A one-factor ANOVA for independent samples conducted on 4
experimental groups, with n = 8 participants in each group,
produces the following partial outcomes: SSbetween = 36, SSwithin =
84. For this analysis, what is the computed F statistic?
A. F = 3
B. F = 12
C. F = 8
D. F = 6
E. F = 21
F. F = 4
2. A researcher reports an outcome of one factor ANOVA for
independent samples as F(2, 36)...

Five population means are being compared. The combined sample
size from all the treatment groups is 200. Complete the ANOVA table
and report the value of the F-test statistic.
Source
df
SS
MS
F
Treatment
Error
12
nothing goes here
Total
2940
nothing goes here
nothing goes here
Group of answer choices
23.8
2.11
11.6
12.5

The following is sample information. Test the hypothesis that
the treatment means are equal. Use the 0.02 significance level.
Treatment 1
Treatment 2
Treatment 3
7
2
5
8
3
7
6
5
10
7
3
6
a. State the null hypothesis and the alternate
hypothesis.
H0:
(The treatment
means are not all the same or The treatment means are the
same?)
H1:
(The treatment
means are not all the same or The treatment means are...

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