Give the upper bound for a 95% confidence interval for a population mean generated from a sample of size n = 10 with a sample mean of x ¯ = 19.8oz and a standard deviation of s = 1.2oz.
Solution :
Given that,
= 19.8 oz.
s = 1.2 oz.
n = 10
Degrees of freedom = df = n - 1 = 10 - 1 = 9
At 95% confidence level the t is ,
= 1 - 95% = 1 - 0.95 = 0.05
t,df = t0.05,9 = 1.833
Margin of error = E = t/2,df * (s /n)
= 1.833 * (1.2 / 10)
= 0.7
The 95% confidence interval estimate of the population mean is,
- E < < + E
19.8 - 0.7 < < 19.8 + 0.7
19.1 < < 20.5
(19.1,20.5)
Upper Bound = 20.5 oz.
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