Question

How to use TI 83/84 to solve for critical value given two independent random samples? (Assume...

How to use TI 83/84 to solve for critical value given two independent random samples?

(Assume 90% confidence interval for true difference between the population means. Assume population variances are not equal and that the two populations are normally distributed.)

Assume for population 1, n=11, x=133, s=20, for population 2, n=12, x=151, s=22.

Math   Statistics-And-Probability   
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Answer #1

Sol:

n1=11

n1-1=11-1=10

alpha=0.10

alpha/2=0.10/2=0.05

0.95

2nd>VARS>DISTR>4:invT

invT(0.95,10)

To get the confidence interval directly in ti 83

STAT>TESTS>2-SampTInt

90% confidence interval for difference in means (-33.07,-2.93)

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