(a)
the prevalence rate of AIDS in the U.S. in 2005.= number of persons living with AIDS in the United States / population of the U.S. in 2005
= ( 397,582. + 40,608 )/ 296,410,404
= 438190/ 296,410,404
= 0.001478
= 0.1478%
So,
Answer is:
0.1478%
(b)
the incidence rate of AIDS in the U.S. in 2005.= number of new cases of AIDS were reported in the U.S. / population of the U.S. in 2005
= 40,608 / 296,410,404
= 0.001370
= 0.0137%
So,
Answer is:
0.0137%
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