Determine the required sample size if you want to be 99% confident that the sample proportion is within 2% of the population proportion if no preliminary estimate of the true population is available.
Solution :
Given that,
= 0.5
1 - = 1 - 0.5 = 0.5
margin of error = E =2 % = 0.02
At 99% confidence level the z is,
= 1 - 99%
= 1 - 0.99 = 0.01
/2 = 0.005
Z/2 = 2.58 ( Using z table )
Sample size = n = (Z/2 / E)2 * * (1 - )
= (2.58 / 0.02)2 * 0.5 * 0.5
=4160.25
Sample size = 4161
( when you have z value 3 decimal answer z=2.576=n=4147.36=4148
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