A train consists of an engine and five cars: I, II, III, IV and V. In how many ways can the cars be arranged so that car I is closer to the engine than car II?
Number of ways the car can be arranged so that car I is closer than car II when it is in first position =1*4!=24
Number of ways the car can be arranged so that car I is closer than car II when it is in second position=3*1*3!=18
Number of ways the car can be arranged so that car I is closer than car II when it is in third position=3*2*1*2!=12
Number of ways the car can be arranged so that car I is closer than car II when it is in fourth position=3*2*1*1*1=6
Number of ways the car can be arranged so that car I is closer than car II =24+18+12+6=60
Get Answers For Free
Most questions answered within 1 hours.