Complete parts (a) and (b) below.
The number of dogs per household in a small town
Dogs |
0 |
1 |
2 |
3 |
4 |
5 |
|
---|---|---|---|---|---|---|---|
Probability |
0.632 |
0.236 |
0.087 |
0.022 |
0.016 |
0.007 |
(a) Find the mean, variance, and standard deviation of the probability distribution.
(b) Interpret the results in the context of the real-life situation.
A.A household on average has
0.90.9
dog with a standard deviation of
0.60.6
dog.
B.A household on average has
0.60.6
dog with a standard deviation of
0.90.9
dog.
C.A household on average has
0.90.9
dog with a standard deviation of
0.90.9
dog.
D.A household on average has
0.60.6
dog with a standard deviation of
1414
dogs.
We know that mean of discrete probability distribution is -
Mean = n * p = 0.6 (Rounded to one decimal places)
and Standard deviation = sqrt [ (x - mean)2 *P(x) ] = 0.9 (Rounded to one decimal places)
Hence B.A household on average has 0.6 dog with a standard deviation of 0.9 is the correct answer.
Hope this will help you. Thank you :)
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